Let
Φ = Flux per
pole, in Wb
P = Number of poles
Ns =
Synchronous speed in r.p.m.
f = Frequency of induced e.m.f. in Hz
Z = Total number of conductors
Zph =
Conductors per phase connected in series
... Zph = Z/3 as number of phases = 3.
Consider a single conductor placed in a slot.
The average value of e.m.f. induced in a conductor
= dΦ/dt
For one revolution of a conductor,
eavg per
conductor = (Flux cut in one revolution)/(time taken for one revolution)
Total flux cut in one revolution is Φ x P
Time taken for one revolution is 60/Ns seconds.
... eavg per conductor = ΦP / (60/Ns)
= Φ (PNs/60)
............. (1)
But
f = PNs/6120
... PNs/60= 2f
... PNs/60= 2f
Substation in (1),
eavg
per conductor = 2 f Φ volts
Assume
full pitch winding for simplicity i.e. this conductor is connected to a
conductor which is 180o electrical apart. So there two e.m.f.s will try to set up a
current in the same direction i.e. the two e.m.f. are helping each other and
hence resultant e.m.f. per turn will be twice the e.m.f. induced in a
conductor.
... e.m.f. per turn = 2 x (e.m.f. per conductor)
= 2 x (2 f Φ)
= 4 f Φ volts
Let Tph be the total number of turn per phase
connected in series. Assuming concentrated winding, we can say that all are
placed in single slot per pole per phase. So induced e.m.f.s in all turns will
be in phase as placed in single slot. Hence net e.m.f. per phase will be
algebraic sum of the e.m.f.s per turn.
... Average Eph = Tph x (Average e.m.f. per turn)
... Average Eph = Tph x 4 f Φ
... Average Eph = Tph x 4 f Φ
But in
a.c. circuits R.M.S. value of an alternating quantity is used for the analysis.
The form factor is 1.11 of sinusoidal e.m.f.
Kf =
(R.M.S.)/Average =
1.11
......... for sinusoidal
... R.M.S. value of Eph = K x Average value
E = 4.44 x f Φ Tph volts ........... (2)
... R.M.S. value of Eph = K x Average value
E = 4.44 x f Φ Tph volts ........... (2)
Note : This is the basic e.m.f. equation for an induced e.m.f. per
phase for full pitch, concentrated type of winding.
Where Tph = Number of turns per phase
Tph = Zph /2 ....... as 2 conductors constitute 1 turn
Tph = Zph /2 ....... as 2 conductors constitute 1 turn
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