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Thursday, July 11, 2013

Pitch factor problem

In a 4 pole, 3 phase alternator, armature has 36 slots. It is using an armature winding which is short pitched by one slot. Calculate its coil span factor.
Solution : 
       n = Slots/pole = 36/4 = 9
       β = 180o/ = 20o
       Now coil is shorted by 1 slot i.e. by 20o to full pitch distance.
...     α = Angle of short pitch = 20o
...      Kc = cos (α/2)  = cos (10)

              = 0.9848

21 comments:

  1. this is no pitch factor but coil factor

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  2. Kc = cos (α/2) = cos (10) this line i din't get it how did u use 2

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  3. Cos(10) is -0.839 and not 0.9848

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    Replies
    1. Your calculator needs to be set in degree to come up with 0.9848.

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  4. What calculator are you using?
    Its 0.984807753

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  5. I dont understand how to find alpha value plz explain.

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    Replies
    1. The alternator have 4 poles and 36 slots. So each pole will have 36/4= 9 slots under it.
      And u know 1 pole = angle of 180° electrica.
      So each slot angle= 180°/9 =20°.
      Now given armature winding is short pitched by one slot.
      So as alpha =shortpitch angle =20°.
      So Kp=cos(20°/2)= cos(10°)

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  6. I dont understand how to find alpha value plz explain.

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  7. If short pitch by 2 slot then alfa is

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  8. How to find distribution factor for same problem?

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    Replies
    1. pitch factor and distribution factor to calculate....please

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  9. how to find distribution factor for same .

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